Recreational Vehicle (RV) Technician Practice Test

In a 12V series circuit with two 8 ohm resistors, what is the amperage draw?

1. 250 mA

2. 500 mA

3. 750 mA

4. 1 A

The correct answer is: 750 mA

To find the amperage draw in a 12V series circuit with two 8 ohm resistors, you first need to calculate the total resistance in the circuit. In a series circuit, the total resistance is the sum of all individual resistances. Therefore, you add the two 8 ohm resistors together: Total Resistance (R_total) = R1 + R2 = 8 ohms + 8 ohms = 16 ohms. Next, you can use Ohm's Law to determine the current (I) flowing through the circuit. Ohm's Law states that I = V / R, where V is voltage and R is resistance. In this case: I = 12V / 16 ohms = 0.75 A or 750 mA. This calculation shows that the amperage draw in the circuit is indeed 750 mA, making this the correct answer. This value confirms that as the overall resistance in the series circuit increases, the current draw decreases, which demonstrates the inverse relationship outlined in Ohm's Law.